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3 years ago

Can anybody help me? I do not understand this

Mathematics

2 answers:

horsena [70]3 years ago

7 0

Can someone help me in my questions I m really stuck

larisa [96]3 years ago

6 0

Answer:

f(0) = 3x : 0

f(1) = 3x : 3

f(2) = 3x : 6

f(3) = 3x : 9

Step-by-step explanation:

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nika2105 [10]

A) 52 square cm I believe is the surface area of the cereal box

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4 years ago

May I also get help on this

iVinArrow [24]

5/9(f-32)
5/9(65-32)= 19.44

3 0

3 years ago

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Three identical fair coins are thrown simultaneously until all three show the same face. What is the probability that they are t

mixer [17]

Answer:

The probability that the coins are thrown more than three times to show the same face is 0.3164.

Step-by-step explanation:

The problem is related to Geometric distribution.

The Geometric distribution defines the probability distribution of X failures before the first success.

The probability distribution function is:

$P(X=k)=(1-p)^{k}p;\ k = 0, 1, 2, ...$

First compute the probability that in the $i^{th}$ throw all the three coins will show the same face.

P (All the 3 coins shows the same face) = P (All the three coins shows Heads) + P (All the three coins shows Tails)

$=(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )+(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} )\\=\frac{1}{8}+\frac{1}{8}\\ =\frac{2}{8} \\=\frac{1}{4}$

Now compute the probability that it takes more than 3 throws for the coins to show the same face.

P (X > 3) = 1 - P (X ≤ 3)

$=1-[P(X=1)+P(X=2)+P(X=3)]\\=1-[[(1-\frac{1}{4} )^{0}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{1}\times\frac{1}{4}]+ [(1-\frac{1}{4} )^{2}\times\frac{1}{4}]+[(1-\frac{1}{4} )^{3}\times\frac{1}{4}]]\\=1-[0.2500+0.1875+0.1406+0.1055]\\=1-0.6836\\=0.3164$

Thus, the probability that it takes more than 3 throws for the coins to show the same face is 0.3164.

8 0

3 years ago

You know of a relative who is addicted to pain killers. Due to his history, 2.3g of Tylenol per day is dangerous. He takes 200 m

Nezavi [6.7K]

Answer: So, your relative takes N tablets each 6 hours. a day has 24 hours, and 24/6 = 4, so he takes N tablets 4 times per day, so he takes 4*N tablets.

each tablet has 200mg, and 2.3 g (or 2300 mg) is toxic.

this means that 4*N*200mg must be less than 2300, if we are seeking for the maximum N possible, then:

4*N*200mg = 2300mg

4*N = 2300/200 = 11.5

N = 11.5/4 = 2.87

if you round up this number, you will end up taking more than 2.3g of tylenol per day, this implies that N must be equal to 2.

So your relative needs to take maximum 2 tablets per day.

7 0

3 years ago

Evaluate 3^2 + (7 − 2) ⋅ 4 − 6 over 3

goldfiish [28.3K]

Answer:

7.7

Step-by-step explanation:

we basically follow the BEDMAS rule

1st we workout the bracket (7-2)=5

2nd the exponent 3^2=9

3rd the multiplication (7-2) . 4 = 5 . 4 = 20

4th addition 9+20=29

5th step is subtraction 29-6=23

the final step is dividing 23 by 3, which will become 7.7

6 0

3 years ago

Read 2 more answers