The given set of values is A = {1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96} The median of this set is 37. Five values are below it; five values are above it. It is the middle most value.
Let L = {1, 5, 27, 29, 34} be the lower set of values smaller than the median. We see that the median of set L is 27. So Q1 = 27
Let U = {48, 61, 72, 84, 96} which is composed of all the values above the median The median of the upper set of values is 72. So Q3 = 72
Subtract the first and third quartile values to get the interquartile range (IQR) IQR = Q3 - Q1 IQR = 72 - 27 IQR = 45
Considering that there is a total number of orders of 10, the amount of bags ordered for the holiday should be 5, given by the ratio of wrapping paper to bags, 5:5.
