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Reil [10]
3 years ago
11

Please, I really need help-

Mathematics
2 answers:
posledela3 years ago
6 0
<h3>Answer: 48</h3>

=====================================================

Explanation:

Triangle ABC is isosceles because AC = BC.

The angles opposite these congruent sides are angle ABC and angle BAC. These are the base angles.

For any isosceles triangle, the base angles are congruent.

Angle BAC = 69 degrees is given. So angle ABC = 69 as well.

-------------------

The missing angle must add to the two other angles so that all three angles in a triangle add to 180

(angle ABC) + (angle BAC) + (angle BCA) = 180

69 + 69 + (angle BCA) = 180

138 + (angle BCA) = 180

angle BCA = 180-138

angle BCA = 42

-------------------

Angle DCE is congruent to angle BCA because they are vertical angles.

Triangle DCE is a right triangle. The missing angle is 90-(angle BCA) = 90-42 = 48

angle EDC = 48 degrees

Aneli [31]3 years ago
4 0

Answer:

48

Step-by-step explanation:

THE ANSWER IS 48 SORRY I CAN SEE IT NOW SORRY

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Find the area of the region enclosed by the graphs of the functions
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Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  • Left to Right<u> </u>

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  • Multiplication Property of Equality
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Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

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Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

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Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

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