Which arrangement shows 275 , 5.36, 535 , and 336 in order from least to greatest

nydimaria [60]

<span>Tan(x)=2
Or for x=45 tan(x)=1
then for tan(x)=2 ; x must be superior to 45
Then the answer is </span><span>d. 63.4 degrees</span>

8 0

2 years ago

The sum of an acute angle and an obtuse angle is an acute angle always sometimes or never true ???

xxTIMURxx [149]

Answer:

Never

Step-by-step explanation:

Adding together an obtuse angle (greater than 90°) and acute angle (less than 90°) should result in an obtuse angle every time

6 0

2 years ago

Read 2 more answers

Gravitational force acts on all object in proportion to their masses. Why then, a heavy object does not fall faster than a light

nordsb [41]

Because force= acceleration x mass Acceleration is constant for a body of any mass since force is exactly proportional to mass.

7 0

1 year ago

Read 2 more answers

A recent survey was conducted to compare the cost of solar energy to the cost of gas or electric energy. Results of the survey r

Mariana [72]

Answer:

c) at most 11.1%

Step-by-step explanation:

We have the data that is 97 ± 12, with 97 being the mean and 12 the standard deviation.

Now, the percentage of people who reached them for less than 73 dollars, if it were a normal distribution:

z = (73 - 97) / 12 = - 2

so it would be, a probability of 0.0228 or 0.228%.

But we don't know what distribution it has, but we can get an idea.

A and D discarded, as they are very high values, and 73 is well below the average.

B) is still a very high value.

Therefore the answer is C, at most 11.1%

4 0

3 years ago

[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =

kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = $1-\frac{_{n}^{12}\textrm{P}}{12^2}$

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= $\frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})$

= $0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1$

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0

2 years ago