Question

Consider this composite figure that is made of two

Answer 1

Answer:

Check Explanation

Step-by-step explanation:

Since the image and dimensions of the composite isn't provided, we will work with what we have.

Let the radius of the two spheres be r.

Let the radius of the cylinder be r too.

Let the height of the cylinder be h.

Volume of a sphere = (4/3)πr³

Volume of a half sphere will be half of the volume of a whole sphere = (2/3)πr³

But we have two half spheres, So, volume of the two half spheres = (2/3)πr³ + (2/3)πr³

= (4/3)πr³

Volume of a cylinder = Bh

where B = area of the circular base of the cylinder = πr²

So, volume of the cylinder = πr²h

So,

Volume of two half spheres = (4r³/3)pi mm³

Volume of the cylinder = (r²h)pi mm³

- Note that, with the way the question is set up, the dimensions of the half spheres and the cylinder are assumed to be in mm.

Volume of composite = (Volume of the two spheres) + (Volume of the cylinder)

Volume of the composite = (4/3)πr³ + πr²h

= πr² [(4r/3) + h] mm³

= r² [(4r/3) + h]pi mm³

Hope this Helps!!!

Answer 2

Answer:

V= 500/3 pi mm ^3  ( sphere)

V= 225 pi mm^3 (cylinder)

Step-by-step explanation:

I guessed and got it right edge 2020