The area of the kite can be found as follows;
Area=[area of XWY]+[areaYWZ]
area XWY=1/2*b*h
=1/2*4*3=6 sq units
area YWZ=1/2*b*h
=1/2*4*4=8 sq units
Hence the area of the kite will be:
Area=6+8=14 sq. units
9514 1404 393
Answer:
14.01, 493, 87
Step-by-step explanation:
Subtracting 28 from both sides tells you the range of values you need to be looking at.
28 + x > 42
x > 14
Any values more than 14 will make the inequality true. Three of them are ...
14.01, 493, 87
L(w) = area of rectangle
x(x+4)
If x = 12...
12(12+4) Distribute the 12 to both terms inside parenthesis.
144 + 48 Add
192 Final Area
I believe the answer is C, 68.
Angles A and R are supplementary so:
180=x+124
Angle A=56
AFD is an isosceles triangle so angles A and D are both 56. Then you can use these to solve for angle AFD.
180 = x+56+56
x=68
I am not sure but I think it's b. Hope this helps
