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2 years ago

Anyone know the answer to this

Mathematics

1 answer:

g100num [7]2 years ago

5 0

Answer:

The answer is d

Step-by-step explanation:

To find out the asnwer, we need to find the value of X. First, we know that X is the same vaule in each equation so we have to find out a number can by multiplied to 9,6, and 5 and get the 3 numbers in either a,b,c, or d. 9x9=81,6x9=54, 5x9=45. These 3 answers matches the number in the choices.

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Is cos 314° positive,negative,or zero?

Oliga [24]

Maybe positive not sure

4 0

2 years ago

Write a quadratic function in standard form with zeros 1 and -10

Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

$f(x)=ax^2+bx+c$

where a,b, and c are constants.

The factored form of a quadratic equation is:

$f(x)=a(x-\alpha)(x-\beta)$

Where $\alpha$ and $\beta$ are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

$f(x)=a(x-1)(x-(-10))$

$f(x)=a(x-1)(x+10)$

Operating:

$f(x)=a(x^2+10x-x-10)$

Joining like terms:

$f(x)=a(x^2+9x-10)$

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

$\boxed{f(x)=x^2+9x-10}$

6 0

3 years ago

Can someone please help it’s very important

densk [106]

Answer:

Step-by-step explanation:

RS is congruent to RV because of SSA or side side angle. RT is congruent to RT is a given. Lines that are perpindicular have right angles which proves angle v=angle s at the same time

5 0

2 years ago

Write a quadratic function in standard form having zeros of -9 and -12

tia_tia [17]

(x + 9)(x + 12) = 0
Expanding the brackets, we get:
$x^{2}+21x+108=0$

3 0

3 years ago

There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin

Ksju [112]

$To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.$

$The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.$

$Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.$

4 0

2 years ago