<h2>y = 10°</h2><h2>∠MKL = 74°</h2><h2>∠JKM = 106°</h2>
<h3>Further explanation</h3>
Firstly , let us learn about trigonometry in mathematics.
Suppose the ΔABC is a right triangle and ∠A is 90°.
<h3>sin ∠A = opposite / hypotenuse</h3><h3>cos ∠A = adjacent / hypotenuse</h3><h3>tan ∠A = opposite / adjacent </h3>
There are several trigonometric identities that need to be recalled, i.e.




Let us now tackle the problem!
This problem is about Supplementary Angles.
∠MKL + ∠JKM = 180°
( 8y - 6 ) + ( 10y + 6 ) = 180°
18y = 180°
y = 180° / 18
<h2>y = 10°</h2>
<h2>∠MKL = ( 8y - 6 )° = (8 ( 10 ) - 6)° = 74°</h2><h2>∠JKM = ( 10y + 6 )° = (10 ( 10 ) + 6)° = 106°</h2>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: College
Subject: Mathematics
Chapter: Trigonometry
Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse