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Sonbull [250]
3 years ago
6

Using the quadratic formula, what is the solution to 2x^2-5x-6=0 ?

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
\bf \textit{quadratic formula}\\

\begin{array}{lcclll}
2x^2&-5x&-6&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\\\\
-----------------------------\\\\
x=\cfrac{-(-5)\pm\sqrt{(-5)^2-4(2)(-6)}}{2(2)}\implies x=\cfrac{5\pm\sqrt{25+48}}{4}
\\\\\\
x=\cfrac{5\pm\sqrt{73}}{4}\implies x=
\begin{cases}
\cfrac{5+\sqrt{73}}{4}\\\\
\cfrac{5-\sqrt{73}}{4}
\end{cases}
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jenyasd209 [6]

Answer:

$1615.05

Step-by-step explanation:

First the cost. We know that tuition per credit hour is 113.67 and there is a flat fee of 660. This can be represented by 113.67h + 660, where h is equal to the number of credit hours.

Next, the amount paid. There are two constants of 350 and 400 already there. We can represent the remaining amount that needs to be paid by another variable, x.

Now, the cost needs to be equal to the amount you pay. We can replace h with 15 for 15 hours and solve for x.

113.67h + 660 = 350 + 400 + x

113.67(15) + 660 = 350 + 400 + x

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USPshnik [31]

Answer:$100

Step-by-step explanation:

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Therefore, the answer is 20.

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3 years ago
I don’t really understand this
mars1129 [50]
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mariarad [96]
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