Using the quadratic formula, what is the solution to 2x^2-5x-6=0 ?

1 answer:

4 0

$\bf \textit{quadratic formula}\\

\begin{array}{lcclll}
2x^2&-5x&-6&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\\\\
-----------------------------\\\\
x=\cfrac{-(-5)\pm\sqrt{(-5)^2-4(2)(-6)}}{2(2)}\implies x=\cfrac{5\pm\sqrt{25+48}}{4}
\\\\\\
x=\cfrac{5\pm\sqrt{73}}{4}\implies x=
\begin{cases}
\cfrac{5+\sqrt{73}}{4}\\\\
\cfrac{5-\sqrt{73}}{4}
\end{cases}$

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Step-by-step explanation:

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