Answer:
1) 2x-5 2) -10/x^2
Step-by-step explanation:
Use power rule and constant rule for the first one:
1) f(x)=x^2-5x^1+1 (x^n)'=nx^(n-1) and (c)'=0
f'(x)=2x^1-5(1)x^0+0
f'(x)=2x-5(1) x^0=1
f'(x)=2x-5
Use just power rule for last one after a rewrite
2) f(x)=10/x
f(x)=10x^(-1) now use power rule
f'(x)=-10x^(-2) =-10/x^2
We have a15 = a1 + 14 x r and a21 = a1 + 20 x r <=> 29 = a1 + 14 x r and 47 = a1 + 20 x r;
Then, 47 - 29 = (20 x r + a1) - (14 x r + a1);
18 = 6 x r;
r = 3;
We have 29 = a1 + 42;
a1 = 29 - 42;
a1 = - 13;
Finally, a5 = a1 + 4 x r = -13 + 4 x 3 = -13 + 12 = -1.
Answer:
D = -4
E = 2
Step-by-step explanation:
The procedure for completing the square method is given as:
x2 + bx + c = 0
x2 + bx = -c
x2 + bx + (b/2)2 = -c + (b/2)2
Aolving the LHS simultaneously,
(x + b)2 = -c + (b/2)2
Find the square root of both sides,
(x + b) = sqrt(-c + (b/2)2)
So for the equation, x2 - 8x + 12
x2 - 8x = -12
x2 - 8x + 16 = -12 + 16
(x - 4)2 = 4
So square root both sides,
(x - 4) = 2
Comparing this to the equation given,
(x - D) = E;
D = -4
E = 2
81 millimeters = 0.00273894 Fluid Ounces
Hope this helps you!
Answer:
if im correct 4.5 hours
Step-by-step explanation:
