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valkas [14]
2 years ago
11

what is the common number to be subtracted from each term of the ratio 11:8 to get the new ratio 2:1.?​

Mathematics
1 answer:
JulijaS [17]2 years ago
7 0

Answer:

5 should be subtracted  from each term

Step-by-step explanation:

\frac{11-x}{8-x}=\frac{2}{1}

Cross multiply,

1 * (11 - x) = 2*(8-x)

11 -x = 2*8 - 2*x

11 - x = 16 - 2x

Subtract 11 from both sides,

-x = 16 - 2x - 11

-x = 5 - 2x

Add 2x to both sides

-x +2x = 5 - 2 + 2x

x = 5

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Which relations are functions?
guapka [62]

Answer:

The 1st and 2nd graph are functions while the 3rd and 4th aren't.

Step-by-step explanation:

The first and second graph doesn't have more than one output for each input. The third and fourth graph isn't a function since there's more than one output for the same input given. If you do the vertical line test, then you'll know which one is a function and which one is not a function. Hope this helps :)

3 0
3 years ago
Melinda rod her bike 54/100 mile to the library. then she rode 4/10 mile to the store. how far did Melinda ride her bike in all?
Lady_Fox [76]
94/100 miles is the answer. I dont know what form you wanted the answer in but yeah.
3 0
3 years ago
HELP PLEASE ASAP IM SO CONFUSED!!!!!!!!
liubo4ka [24]

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept → (0, b)

We have the points (-4, -6) and (2, 6). Substitute:

m=\dfrac{6-(-6)}{2-(-4)}=\dfrac{12}{6}=2\\\\y=2x+b

Put the coordinates of the point (2, 6) to the equation of a line:

6=2(2)+b\\\\6=4+b\qquad|-4\\\\2=b\to b=2

<h3>Answer: y = 2x + 2</h3>
8 0
3 years ago
1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.
iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is 53.13\°

Part 2) The surface area of the pyramid is 288\ cm^{2}

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

sin(x)=\frac{16}{20}

x=arcsin(\frac{16}{20})=53.13\°

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}(b)(h)]

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

h=b/2 -------> by an 45° angle

so

b=2h

sin(45\°)=\frac{h}{6\sqrt{2}}

h=6\sqrt{2}(sin(45\°))=6\ cm

Find the value of b

b=2(6)=12\ cm

Find the surface area

SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}

3 0
3 years ago
12. AABC is a right triangle. If AB = 3 and AC = 7, find BC. Leave your answer in simplest radical form.
never [62]

Answer:

b

Step-by-step explanation:

You multiply from left to right

3 0
3 years ago
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