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Darina [25.2K]
3 years ago
10

What is an equation of the line that passes through the points (6, -5) and (3,0)?

Mathematics
2 answers:
Aliun [14]3 years ago
7 0

Step-by-step explanation:

Hey there!

The equation of a st.line passing through points (6,-5) and (3,0) is;

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

[Using double point formula]

Now, Put all values,

(y  + 5) =  \frac{0 + 5}{3 - 6} (x - 6)

Simplify it to get equation.

(y + 5) =   - \frac{5}{3} (x - 6)

3(y + 5) =  - 5(x - 6)

3y + 15 =  - 5x + 30

5x + 3y + 15 - 30 = 0

5x + 3y - 15 = 0

Therefore the required equation is 5x + 3y - 15 = 0.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

miskamm [114]3 years ago
7 0

Answer:

y = -5/3x + 5

Step-by-step explanation:

The formula for the equation of a line is :

y - y1 = m (x-x1)

m is the gradient

<h2><u>finding the gradient</u></h2>

formula

\frac{y2-y1}{x2-x1} \\\\

= (0--5)/ (3-6)

=5 / -3

<u>gradient = - 5/3</u>

<u></u>

<h2><u>inserting the values in formula for the equation of a line </u></h2>

y - y1 = m (x-x1)

y - -5 = -5/3 (x - 6 )

y + 5 = -5/3 x + 10

y = -5/3x + 10 - 5

<em><u>y = -5/3x + 5 </u></em>

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