Answer:
a. 45 π
b. 12 π
c. 16 π
Step-by-step explanation:
a.
If a 3×5 rectangle is revolved about one of its sides of length 5 to create a solid of revolution, we can see a cilinder with:
Radius: 3
Height: 5
Then the volume of the cylinder is:
V=π*r^{2} *h= π*(3)^{2} *(5) = π*(9)*(5)=45 π
b. If a 3-4-5 right triangle is revolved about a leg of length 4 to create a solid of revolution. We can see a cone with:
Radius: 3
Height: 4
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(3)^{2} *(4) = (1/3)*π*(9)*(4)=12 π
c. We can answer this item using the past (b. item) and solving for the other leg revolution (3):
Then we will have:
Radius: 4
Height: 3
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(4)^{2} *(3) = (1/3)*π*(16)*(3)=16 π
Answer:
y+2= 3(x+1)
Step-by-step explanation:
First you need to find slope by using y2-y1/x2-x1
you should get 3 for your slope(m)
Them you chose any point iḿ using (-1, -2)
The formula for point slope form is...
y-y1=m(x-x1)
plug those numbers in and you get
y + 2 = 3(x + 1)
I'm assuming you want an equation with a slope of -5 that also passes through the point (1, -7).
An equation that fits this is

Hope this helps!
Answer:
go to the left to -85 then go up to 52.
Step-by-step explanation:
x=-85
y=52
Answer:
DNE
Step-by-step explanation:
Given that two particles travel along the space curves

To find the points of intersection:
At points of intersection both coordinates should be equal.
i.e. r1 =r2
Equate corresponding coordinates

I equation gives t =-1
Substitute in II equation to get 
i.e. t cannot be real
Hence no point of intersection
DNE