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dlinn [17]
3 years ago
15

Some species of hummingbirds appear to hover in mid-air by flapping their tiny wings 80 times per second. How many times per min

ute do hummingbirds flap their wings?
Mathematics
1 answer:
astraxan [27]3 years ago
3 0
So the way to answer this question is to convert minute to seconds
We know that a minute has 60 seconds
The problem states that the hummingbird flaps its wings 80 times per second
So 80 times per second x 60 seconds = 4800 times would be the final answer.
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Write the equation of the line for the given point and slope
AnnZ [28]
Well im not to sure about this one loook it up
8 0
3 years ago
If you are good at sequences in math please help I am giving more points
vodka [1.7K]

Answer:

C. 101 - 5(n - 1)

Step-by-step explanation:

d = (26 - 71)/(16 - 7)

d = -45/9

d = -5

a7 = a1 + (7-1)(-5)

71 = a1 - 30

a1 = 101

an = 101 + (n - 1)(-5)

an = 101 - 5(n - 1)

4 0
3 years ago
Read 2 more answers
X-y=-5<br> x-y=1^3<br> help pleas --- solve equations by substitution.
V125BC [204]

Heya!

Answer is No \: Solution

<u>EXPLANATION</u><u> </u><u>:</u><u>-</u>

Given

x-y= -5

x-y=1³

Substitute value of x - y as 1³ in first equation,

=> x-y= -5

=> 1³ = -5

As we can't do anything more to solve, we can finally write as :

No \: Solution

~ Benjemin360

7 0
3 years ago
The slope of a line is -1/3. Find the slope of a line that is perpendicular to this line. Help please, correct answers and an co
Licemer1 [7]

Answer:

slope = 3

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m}

Given m = - \frac{1}{3}, then

m_{perpendicular} = - \frac{1}{-\frac{1}{3} }  = 3

6 0
4 years ago
Is x=10 a solution to this equation? 3x2 = 900
bixtya [17]
3(10)^2 = 900

300 = 900

false; X=10 is not a solution
5 0
3 years ago
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