All categories

3 years ago

Find f(-5) if f(x)=|x+1|

Mathematics

2 answers:

Grace [21]3 years ago

7 0

F(x)=|x+1|
f(-5)=|-5+1|
f(-5)=|-4|
f(-5)=4. As a result, f(-5)=4 is the correct answer. Hope it help!

Stella [2.4K]3 years ago

3 0

Answer:

$f(-5)=4$

Step-by-step explanation:

we have

$f\left(x\right)=\left|x+1\right|$

we know that

$f(-5)$ is the value of the function for the value of $x=-5$

Substitute the value of $x=-5$ in the function

$f\left(-5\right)=\left|-5+1\right|$

$f\left(-5\right)=\left|-4\right|=4$

$f(-5)=4$

You might be interested in

Solve in attachment....

olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

$\displaystyle \int_{0} ^{1} 5x \sqrt{x} dx$

use constant integration rule which yields:

$\displaystyle 5\int_{0} ^{1} x \sqrt{x} dx$

notice that we can rewrite √x using Law of exponent therefore we obtain:

$\displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx$

once again use law of exponent which yields:

$\displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx$

use exponent integration rule which yields;

$\displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1}$

simplify which yields:

$\displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1}$

recall fundamental theorem:

$\displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)}$

simplify:

$\displaystyle 2$

hence

our answer is A

8 0

2 years ago

Read 2 more answers

What is 0.000025(800)^2 - 0.04(800) +40..?

Scilla [17]

Answer:

Step-by-step explanation:

6 0

2 years ago

Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con

andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

7 0

3 years ago

47. What is the 12th term of the geometric sequence?

GrogVix [38]

Answer:

Step-by-step explanation:

The rule is 2x.

So 3,6,12,24,48,96,192,384,768,1536,3072,6144,12288,....

The question asked for the 12th term so 6144.

5 0

3 years ago

Read 2 more answers

You spend two and a half hours online you spend one fifth of that time writing a blog how long do you spend writing your blog

sveta [45]

Answer:

u spend half an hour on your blog

Step-by-step explanation:

(1/5)*(5/2) = 1/2

4 0

2 years ago