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4 years ago

Please solve the proof

Mathematics

1 answer:

Alenkinab [10]4 years ago

7 0

Answer:

$\pi \pi \neq x^{2}$

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$ $\lim_{n \to \infty} a_n$

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Okay so this is a weird one... if I take a medication twice a day for 9 months how many days have I taken that medication??? I h

Delvig [45]

Answer: 273 days i believe

Step-by-step explanation:

jan: 31 days

feb: 28 Days

mar: 31

apr: 30

may: 31

june: 30

july: 31

aug: 31

sept: 30

add all the days together to get 273

7 0

3 years ago

Tyler makes a sign that is 79 yard long and 23 yard wide. What is the area of his sign in square yards?

Hitman42 [59]

Answer:

$A=1817\ \text{yards}^2$

Step-by-step explanation:

Given that,

The length of sign, l = 79 yard

Width, b = 23 yards

We need to find the area of his sign. It is in the form of a rectangle. The area of a rectangular shape is given by :

$A=l\times b\\\\A=79\times 23\\\\A=1817\ \text{yards}^2$

So, the area of his sign is $1817\ \text{yards}^2$ .

3 0

3 years ago

Solve for F. Show EACH step for full credit. Circle your final answer.

Studentka2010 [4]

Answer: 5/2f+15

Step-by-step explanation:

2d−5f+5f=30+5f

Then,

2d=5f+30

Next,

2d/2 =5f+30/2

3 0

4 years ago

Read 2 more answers

In January, a toy store sold 846 puzzles. Each puzzle cost $5, including tax. What was the total cost of the puzzle sold, includ

scZoUnD [109]

Answer:

$4,230

Step-by-step explanation:

There are 846 puzzles sold and including tax, it is $5 per puzzle. Multiply the amount of puzzles by cost and you get the total cost of all puzzles sold including tax.

6 0

3 years ago

Read 2 more answers

Factor the polynomial completely.

Mrrafil [7]

Answer:

The factors of the polynomial: (b⁴ - 2)(b² - 3)

Step-by-step explanation:

The given polynomial is: $\textbf{b}^{\textbf{6}} \textbf{-3b}^{\textbf{4}} \textbf{-2b}^{\textbf{2}} \textbf{+ 6}$

We can factor the given polynomial by grouping.

We get: $\{ b^6 - 3b^4\} + \{2b^2 + 6\}$

$= b^4 (b^2 - 3) -2(b^2 - 3)$

Taking (b² - 3) common outside, we get:

$= \{b^2 - 3\} \{b^4 - 2\}$

Hence the polynomial $b^6 - 3b^4 - b^2 + 6$ can be factored as $(b^4 - 2)(b^2 - 3)$ .

Hence, the answer.

7 0

4 years ago