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Sergio [31]
4 years ago
15

Factor the polynomial completely.

Mathematics
1 answer:
Mrrafil [7]4 years ago
7 0

Answer:

The factors of the polynomial: (b⁴ - 2)(b² - 3)

Step-by-step explanation:

The given polynomial is: $ \textbf{b}^{\textbf{6}} \textbf{-3b}^{\textbf{4}} \textbf{-2b}^{\textbf{2}} \textbf{+ 6} $

We can factor the given polynomial by grouping.

We get: $ \{ b^6 - 3b^4\} + \{2b^2 + 6\} $

$ = b^4 (b^2 - 3) -2(b^2 - 3) $

Taking (b² - 3) common outside, we get:

$ = \{b^2 - 3\} \{b^4 - 2\} $

Hence the polynomial $ b^6 - 3b^4 - b^2 + 6 $ can be factored as $ (b^4 - 2)(b^2 - 3) $.

Hence, the answer.

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