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Burka [1]
3 years ago
7

What is the solution to the system of equations?

Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

(7, 13/3)

Step-by-step explanation:

y=\frac{1}{3} x+2\\   Line up the equations on top of each other

y=\frac{4}{3} x-5

-4*[y=\frac{1}{3} x+2]   Multiply the top equation by -4 in order to cancel out the x variable

-4y=-\frac{4}{3} x-8   Switch out the first equation for this one

-4y=-\frac{4}{3} x-8   Line up the equations

    y=\frac{4}{3} x-5

-3y=-13   Add the two equations top to bottom, left to right

    y=\frac{13}{3}

Now that you've found y, you need to find x. Just plug in the y-value to either of the equations in Step 1:

The first equation has smaller numbers, so let's use that one.

\frac{13}{3} =\frac{1}{3} x+2

To make it easier you can multiply all the terms in the equation by 3:

13=x+6

 7=x

The x- and y- values together give a solution of ( 7, \frac{13}{3} )

Alisiya [41]3 years ago
5 0
Solve systems of equations by graphing. A system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system.
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Maria needs to reach a window that is eight feet above the ground. When she placed a ladder so that it reached the bottom of the
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Answer:

10 feet

Step-by-step explanation:

Given that the distance to be reached is 8 feet above ground and she she placed a ladder so that it reached the bottom of the window, the base of the ladder was 6 feet from the house, the length of the ladder considered with the other lengths forms a right angled triangle.

The length of the ladder represents the hypotenuse side hence using pythagoras theorem

F^2 = 8^2 + 6^2

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3 years ago
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Shkiper50 [21]

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4 0
2 years ago
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Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y
mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Step-by-step explanation:

Given the data in the question;

y = y = e^{(x - 1 ), y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = y = e_2}^{(x - 1 )_, y = 0

Volume = \pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx

Volume = \pi \int\limits^2_1 ( e^{x-1)^2  dx

Volume = \pi \int\limits^2_1 e^{2x-2}dx

Volume = \frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx

Volume = \frac{\pi }{e^2}  [\frac{e^{2x}}{2}]^2_1

Volume = \frac{\pi }{2e^2}  [e^4 - e^2 ]  

Volume = \frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

   

3 0
3 years ago
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