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Volgvan
3 years ago
11

Which describes the relationship between ZNOM and ZJOK in the diagram?

Mathematics
1 answer:
sveta [45]3 years ago
7 0

Answer:

the anwser is: B: Supplementary Angles

Step-by-step explanation:

so first you look at NOM and JOK and then you look at the anwsers. B is the most relevant because a supplementary angle means that the angles are 180 degrees.and they are... so yeah its b

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Which is greater 2/6 or 1/3
tino4ka555 [31]
They are equal because if you simplify 2/6 then that will equal 1/3 so the problem is 1/3 _1/3 and that will be =
4 0
3 years ago
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Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
Endpoint: (9,-10), midpoint: (4,8)
Alika [10]

Answer:

( -1 , 26)

Step-by-step explanation:

So since you need to find the other endpoint, you would follow these steps:

1.) 4 = \frac{9 + x}{2\\}

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3.) -1 = x  (just solve it like a regular equation, so just subtract 9 on both sides                  to get rid of it and that leaves you with -1 = x)

You took the x values of both points and put them in the equation.

And its the same for y

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5 0
3 years ago
Contains the x intercept of 4x-y=8 and the point (-4,3)
nydimaria [60]
<span>1.       </span><span>4x –y = 8, the point (-4, 3)
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=> 4x – 8
=> 4x / 4 = 8 /4
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Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=>  m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>



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3 years ago
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$9147 x 12 =190,764
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