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Oksi-84 [34.3K]
4 years ago
12

Sara claims that the number of pages she has read in her book is proportional to the number of minutes that she has spent readin

g.  She collects several data points to prove her claim and expresses the data points as (x, y) coordinate pairs.
Mathematics
1 answer:
nikitadnepr [17]4 years ago
4 0
X = 77.789
y = 23...............................
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The students in Eddie's grade voted to select a guest speaker, 20% of the students voted
gulaghasi [49]

Answer:15

Step-by-step explanation:

0.2*75=15 students

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3 years ago
I NEED HELP REALLY BAD!
katen-ka-za [31]
<h2>Answer:</h2>

<u>The area is</u><u> 168 yd²</u>

<h2>Step-by-step explanation:</h2>

The area of Trapezoid is given by

A= (a+b)/2 * h

Putting the values

A = (5+23)/2 * 12

A = 168 yd²

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3 years ago
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What is the equivalent ratio for 3:4​
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Answer:

A ratio of 1/2 can be entered into the equivalent ratio calculator as 1:2. 2/10 would be 2:10, 3/4 would be 3:4 and so on.

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3 years ago
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I need to solve this using l'hopital's rule and logarithmic diferentiation.
arlik [135]

Yo sup??

For our convenience let h=x+1

therefore

when x tends to -1, h tends to 0

hence we can rewrite it as

\lim_{h \to \ 0 } (cos(h))^{(cot(h^2 )}

This inequality is of the form 1∞

We will now apply the formula

e^(^g^(^x^)^(^f^(^x^)^-^1^)^)

plugging in the values of g(x) and f(x)

e^{lim_{h \to \ 0}{(cot(h)^2(cos(h)-1))}

express coth² as cosh²/sinh² and also write cosh-1 as 2sin²(h/2)

(by applying the property that cos2x=1-sin²x)

After this multiply the numerator and denominator with h² so that we can apply the property that

\lim_{x \to \ 0 } sinx/x =1

Now your equation will look like this.

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2)*h^2)/(sin(h)^2*h^2)}

We will now apply the result

\lim_{x \to \ 0 } sinx/x =1

where x=h²

we get

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2)}

we now multiply the numerator and denominator with 4 so that we can say

\lim_{h^2 \to \ 0 } sin^2(h/2)/(h^2/4) = 1

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2*4/4)}

=e^{lim_{h \to \ 0}{((cos(h)^2*2)/(4)}

Apply the limits and you will get

e^{cos(0)^2*2/4

=e^{1/2}

Hope this helps.

7 0
3 years ago
What’s the value of x? <br> y= 5x + 9<br> y= -x + 3
ser-zykov [4K]

Answer:

x=-1 y=4                                (-1,4)

Step-by-step explanation:

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