Question

In right triangle ABC, sin M = cos 61. If 0

Answer 1

Note: Consider we need to find the value of M if $0^\circ$

Given:

In a right triangle ABC,

$\sin M=\cos 61^\circ$

To find:

The value of M.

Solution:

We have,

$\sin M=\cos 61^\circ$

It can be rewritten as:

$\sin M=\cos (90^\circ-29)^\circ$

$\sin M=\sin 29^\circ$                   $[\because \sin (90^\circ-\theta)=\sin \theta]$

On comparing both sides, we get

$M=29^\circ$

Therefore, the value of M is 29 degrees.