<h2>Answer</h2>
2
<h2>Explanation</h2>
First, we are going to use the law of fractional exponents: ![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
We can infer form our expression that 
and 
, so let's replace the values:
![16^{\frac{1}{4} }=\sqrt[4]{16}](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%3D%5Csqrt%5B4%5D%7B16%7D)
Notice that we can also decompose 16 into prime factors to get 
, so we can rewrite our expression as follows:
![\sqrt[4]{16}=\sqrt[4]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%5Csqrt%5B4%5D%7B2%5E4%7D)
Finally, we can use the rule of radicals: ![\sqrt[n]{a^n} =a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%20%3Da)
, so:
![\sqrt[4]{2^4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E4%7D%3D2)
ANSWER
Option D
EXPLANATION
The parent radical function is
The transformed function is
This is a transformation of the form.
which shifts the parent function horizontally by k units to the right and stretches the parent function vertically by a factor of 'a'.
In this case a=2 and k=3,
there is a horizontal shift of 3 units to the right and a vertical stretch by a factor of 2.
The last choice is correct.
Answer:
80% Confidence interval: (0.4603,0.7397)
Step-by-step explanation:
We are given the following in the question:
Sample mean, 
= MD = 0.60 points
Sample size, n = 9
Sample variance = 0.09
Sample standard Deviation =
80% Confidence interval:
Putting the values, we get,
