If there are 14 tens, that is 14 multiplied by 10. 14 x 10 = 140.
140 is the answer.
Hope this helps :)
The probability of getting tails and rolling an odd number is P = 0.25
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How to get the probability?</h3>
The probability of getting tails on the coin is 0.5
On the dice, there are 6 numbers and 3 are odd, so the probability of rolling an odd number is:
p = 3/6 = 0.5
The joint probability (of getting tails and rolling an odd number) is equal to the product between the individual probabilities:
P(odd and T) = 0.5*0.5 = 0.25
If you want to learn more about probability:
brainly.com/question/25870256
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Since k is constant (the same for every point), we can find k when given any point by dividing the y-coordinate by the x-coordinate.
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
