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2 years ago

Finding actual height and width of a room

Mathematics

1 answer:

sladkih [1.3K]2 years ago

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10 times as much as 700

Dmitry_Shevchenko [17]

The answer is 7000
Because u do 700 ten times so it would be
700x10
=7000 Please give brainliest

8 0

2 years ago

Can anyone Explain in words why these are equivalent expressions.

N76 [4]

Answer:

The distributive property says that when there is a number outside of parenthesis, this means it should be distributed (or multiplied) to the values inside the parenthesis.

So in this situation, 10 x b = 10b

and 10 x 4c = 40 c

so 10(b + 4c) becomes 10b + 40c once the 10 is distributed within the parenthesis.

I hope this helps!

4 0

3 years ago

Read 2 more answers

What inequality is graphed below?

boyakko [2]

Answer:

B. x ≤ 2.5

Step-by-step explanation:

a and d say 3 which is wrong

either b or c

the filled in dot at the line indicates this is inequality

so its b

5 0

2 years ago

En considérant que DE est

skad [1K]

Answer:

Step-by-step explanation:

5 0

2 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

3 years ago