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sladkih [1.3K]
3 years ago
12

Calculate the number of ways to form a set of three distinct items such that no two of the selected items are in the same row or

same column
Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

1200

Explanation:

Order does not matter, if we said xyz order, it would still not make a difference if it was zyx or yzx hence we use the combination formula:

nCr = n! / r! * (n - r)!

where n= total number of items

r= number of items chosen at a time

Combinations are used when the order of events do not matter in calculating the outcome.

We calculate using the formula:

(30×20×12)÷3!=1200

There are therefore 1200 ways for the three distinct items to not be in same row or column

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aleksandr82 [10.1K]
1/3 is 0.33.. and 1/4 is .25 , so the answer is 1/4
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If F(x) = 5x - 7 and G(x) = {x+13, what is G(F(x))?
devlian [24]

Answer:

option B

Step-by-step explanation:

G(x) = \sqrt{x} +13

F(x)= 5 x-7

G(F(x)) = \sqrt{5x-7} +13

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Draw the image of ABC under the translation (x, y)
Neko [114]

Answer:

Step-by-step explanation:

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2 years ago
Recent survey data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. Their parents must have
astraxan [27]

Answer:

38.76% probability that between 13 and 17 of these young adults lived with their parents

Step-by-step explanation:

I am going to use the normal approxiation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.142, n = 125

So

\mu = E(X) = np = 125*0.142 = 17.75

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.142*0.858} = 3.9025

What is the probability that between 13 and 17 of these young adults lived with their parents?

Using continuity correction, this is P(13 - 0.5 \leq X \leq 17 + 0.5) = P(12.5 \leq 17.5), which is the pvalue of Z when X = 17.5 subtracted by the pvalue of Z when X = 12.5. So

X = 17.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{17.5 - 17.75}{3.9025}

Z = -0.06

Z = -0.06 has a pvalue of 0.4761

X = 12.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{12.5 - 17.75}{3.9025}

Z = -1.35

Z = -1.35 has a pvalue of 0.0885

0.4761 - 0.0885 = 0.3876

38.76% probability that between 13 and 17 of these young adults lived with their parents

4 0
3 years ago
Select the graph that represents the equation (x-6)^2+(y+7)^2=16
wlad13 [49]

This is how the graph should look, hope this helps

5 0
3 years ago
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