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3 years ago

What is 2.25 as a improper fraction

Mathematics

2 answers:

MariettaO [177]3 years ago

8 0

Answer: 225/100

Step-by-step explanation:

2.25 as an improper fraction

200 + 25/100

225/100

navik [9.2K]3 years ago

3 0

~ Convert the decimal number to a fraction by placing the decimal number over a power of ten.

~ Next, add the whole number to the left of the decimal.

2 25/100

~ Reduce the fractional part of the mixed number.

2 1/4

Answer: 2 1/4

Hope this helps :)

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Step-by-step explanation:

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Look at the graph below measuring the speed of a truck and answers the following 2 question.

NemiM [27]

X would be equal to time and y be equal to distance

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3 years ago

What's the answer to: divide £48 in the ratio 7:5 (please show your working, much appreciated)

Brums [2.3K]

I can see you come from outside the USA. No insults intended!!
.
Anyways, we have to put one side of the ratio and match it to 48.
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Or even better...
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MAKE!!
A!!
PROPORTION!!
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So... Let's say 7 is proportional to 48... so 7/5 = 48/x, where x is the number equivalent to ratio of 5.
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Cross multiply!!
<span>.
</span>7x = 240.
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Divide 7 on both sides.
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x = 34 2/7.
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Hope I helped!!

4 0

3 years ago

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

4 years ago