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oksano4ka [1.4K]
3 years ago
10

Help i will give brainliest

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

Step-by-step explanation:

Area of circle = 56 cm²

                   πr² = 56

                 3.14r² = 56

                         r²=56/3.14

                        r²= 17.83

                        r = √17.83

                        r = 4.22 cm

The diameter of the circle  = diagonal of the square

Diagonal of the square = 2 * 4.22 = 8.44 cm

x² + x² = 8.44²

2x² = 71.2336

  x² = 71.2336/2

  x² = 35.6168

x = 5.967 cm

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I will mark brainlist to whoever answers first
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Answer:

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Step-by-step explanation:

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Use the Midpoint Rule and the given data to estimate the value of the integral I. (Give the answer to two decimal places.)
svlad2 [7]

Answer:

a) integral = 24.72

b) |Error| ≤ 0.4267

Step-by-step explanation:

a)

The integral:

\int_{0}^{3.2} f(x) dx

can be  approximated with the midpoint rule, as follows:

6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72

(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)

b)The error bound for the midpoint rule with <em>n</em> points is:

|Error| ≤ K*(b - a)^3/(24*n^2)

where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|

Given that -5 ≤ f''(x) ≤ 1, then K = 5.  Replacing into the equation:

|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267

5 0
3 years ago
The answer appears incorrect, please help me correct it :)
UNO [17]

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3 years ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

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We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

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56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

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So we found our angle of rotation, which is 106.26

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Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

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\frac{10626}{360}  - 48

Which is an approximate or

44.73

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5ft 6in = 66 in
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