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Komok [63]
4 years ago
5

The play took in $728 one night. The number of $8 adult tickets was 14 less than twice the number of $5 child tickets. How many

of each ticket were sold
Mathematics
1 answer:
astra-53 [7]4 years ago
8 0

Answer:

  • adult: 66
  • child: 40

Step-by-step explanation:

Let c represent the number of child tickets sold. Then 2c-14 is the number of adult tickets sold, and total revenue is ...

  5c +8(2c-14) = 728

  21c -112 = 728 . . . . . . simplify

  21c = 840 . . . . . . . . . . add 112

  c = 40 . . . . . . . . . . . . . divide by 21

  2c-14 = 66 . . . . . . . . . number of adult tickets sold

66 adult tickets and 40 child tickets were sold.

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The final task is a bit more difficult. The bookshelf consists of two cubes and each cube has a side of (1/2). This is a fractio
hodyreva [135]

Answer:

1/4

Step-by-step explanation:

I think that the expression is correct

(1/2)^3 x 2 = 1/8 x 2 = 1/4

6 0
3 years ago
There are many ways to produce crooked dice. To load a die so that 6 comes up too often and 1 , which is opposite 6 , comes up t
Andreas93 [3]

Answer:

1            2                  3             4            5       6

2 ÷ 15   1 ÷ 6           1 ÷ 6        1 ÷ 6     1 ÷ 6    1 ÷ 5

Step-by-step explanation:

As it is mentioned in the question that the probability of faces like 2,3,4,5 are not affected so in this case

P(2) = P(3) = P(4) = P(5) = 1 ÷ 6

And,  P(6) = 0.2

As we know that

P(1) + P(2) +P(3) +P(4) +P(5) +P(6) = 1

This results P(1) = 2 ÷ 15

So,

1            2                  3             4            5       6

2 ÷ 15   1 ÷ 6           1 ÷ 6        1 ÷ 6     1 ÷ 6    1 ÷ 5

Hence, the correct option is 2nd

4 0
3 years ago
What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²
AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting coordinates A and C we get

l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit

Similarly for BD we have,

l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit

Now Substituting AC and BD in Formula we get

\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD

\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}

Therefore the Area of Rhombus ABCD is 36 unit².

6 0
3 years ago
Help please ;-;
anzhelika [568]

Answer:

could be either b or d

Step-by-step explanation:

3 0
3 years ago
Brayden was out at a restaurant for dinner when the bill came. His dinner came to $22. After adding in a tip, before tax, he pai
sesenic [268]

Answer:

Step-by-step explanation:

Your answer

Price = 22$

TIP IN PRICE = 28.6$

Tip in discount = 30%

Mark it as Brainlist answer. Follow me.

6 0
3 years ago
Read 2 more answers
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