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Komok [63]
3 years ago
5

The play took in $728 one night. The number of $8 adult tickets was 14 less than twice the number of $5 child tickets. How many

of each ticket were sold
Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

  • adult: 66
  • child: 40

Step-by-step explanation:

Let c represent the number of child tickets sold. Then 2c-14 is the number of adult tickets sold, and total revenue is ...

  5c +8(2c-14) = 728

  21c -112 = 728 . . . . . . simplify

  21c = 840 . . . . . . . . . . add 112

  c = 40 . . . . . . . . . . . . . divide by 21

  2c-14 = 66 . . . . . . . . . number of adult tickets sold

66 adult tickets and 40 child tickets were sold.

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If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?
Ludmilka [50]

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Step-by-step explanation:

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7 0
2 years ago
Which of these sets of angle measures could be the three angles in a triangle?
Lady_Fox [76]

Answer:

Okay so this is simple addition, once you know how to do it. 

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7 0
3 years ago
Which inequality best represents the situation in which you must be at least 42 inches tall to ride the roller coaster
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42  \leq x

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HELP PLEASE ASAP
kondaur [170]
Answer: D. $3,450
Given: 2,500 shares of a stock bought for $8 a share
<span>Probabilities:  the stock will rise to a value of $32 a share is 22%</span>  <span>                                                the stock will fall to $3 a share is 78%</span>
<span>Question: What is the expected value of the investor’s profit from buying the stock?</span>
Solution: (22%(32-8)-78%(8-3))2500
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                (5.28-3.9)2500
                (1.38)2500
                3450
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