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kiruha [24]
3 years ago
8

What is 3/4*16/21 Simplify fractors

Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

\bf \cfrac{3}{4}\cdot \cfrac{16}{21}\implies \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 4}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 7}\implies \cfrac{4}{7}

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the track at Morgans School is 1/4 mile long. he runs 8 laps around the track how far did Morgan run?
jarptica [38.1K]
8 * 1/4 = 8/4 = 2 miles <==
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3 years ago
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A coin is tossed three times. what is the probability of getting two heads and one tail?
Lera25 [3.4K]
If the order doesn't matter, then the probability is 37.5%
If it has to be head head tail, then the probability is 12.5%

If the order doesn't matter, the possible outcomes that have two heads and one tail are HHT, HTH, and THH. Since these all have a probability of 12.5% of occuring, the probability of any of them occuring is 37.5%
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What is the solution set of 2 x(x-1) =3?​
Llana [10]

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Step-by-step explanation:

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3 years ago
0.2(10-5c)=5c-16 halp
iogann1982 [59]

Answer:

c= 3

Step-by-step explanation:

0.2(10 -5c)= 5c -16

<em>Expand</em><em>:</em>

0.2(10) +0.2(-5c)= 5c -16

2 -c= 5c -16

<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

5c +c= 2 +16

<em>Simplify</em><em>:</em>

6c= 18

<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

c= 18 ÷6

c= 3

5 0
3 years ago
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Find the sum of the interior angle measure of a regular polygon with 20 sides
AleksAgata [21]

Answer:

3240°

Step-by-step explanation:

For a regular icosagon,

sum of interior angles measure=180(n-2)°

180(20-2)

180(18)=3240°

8 0
3 years ago
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