Answer:
3/5
Step-by-step explanation:
3 is the X and 5 is the Y add together you get 8
but the answer is 3/5 from point C to B
The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.
<h3>Define the term (distribution) transparency?</h3>
Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.
- The DDBMS designer has the option of replicating table fragments, storing them at several locations, and fragmenting tables.
- There are numerous distribution methods. Systems that need a wide range of management systems to pinpoint the source of resources, a product, or a service delivery process from the end user.
- Typically, the distributor, seller, or producer is responsible for maintaining transparency to track the many points at which resources, goods, or services are delivered.
- Accounting supplied by any intermediary company in the product, service, or resource flow is, of course, the usual approach to determine the degrees of value added through distribution management.
Thus, access transparency, location transparency are some examples of the (distribution) transparency.
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<span>prime factors are prime numbers that can be multiplied to give the number.
to find the prime factors the number is divided by the prime numbers by which the number is divisible.
24 / 3 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
24 is divisible by 3 , 2 , 2 and 2.
therefore 24 written as a product of its prime factors is 24 = 2 x 2 x 2 x 3</span>
Answer:Bill
Step-by-step explanation:
Because Bill scored to the nearest 100
E-3 will be the first student to start writing the assignment.
It is clearly stated in the statement that the order of starting the assignment and the order of the completion of the assignment is not the same, the digit in the name of the executive is also not same. This information puts some restrictions.
E-1 can neither be the first one to start nor the first one to complete. Similarly, E-2 cannot be the second one and E-3 cannot be the third one.
It is given that the last student (the third one) to start is the first student (the first one) to complete. This can neither be E-3 nor E-1. It is E-2
The final arrangement is as follows.
Start Complete
First E-3 E-2
Second E-1 E-3
Third E-2 E-1
E-3 is the first one to start writing the assignment.
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