Find the area and perimeter of the figure below, explain and show work pls

Mathematics

2 answers:

irina1246 [14]3 years ago

8 0

Answer:

area is 26.285cm² permiter is 28.565 cm

Step-by-step explanation:

area

so split the shape into smaller shapes

half- circle

area of a circle is πr^2 so πx4^2 is 12.57 so half this number to get area of a half- circle =6.285cm2

rectangle area = (2+4+2) x 1= 8cm2

triangle area is 1/2 base x height

so 1/2 8 X 3 = 4 x 3= 12 cm2

add them all up 6.285 + 8 + 12= 26.285cm2

perimeter

do it bit by bit again

perimeter of half circle

for full circle =2πr^2 so = 25.13

for half circle= 12.565cm

rectangle part = 2+2+1+1 = 6cm

triangle part =5+5 = 10cm

total perimeter = 12.565+6+10= 28.565 cm

Stels [109]3 years ago

7 0

This is my work and only part 1

You might be interested in

How can you express (15 + 30) as a multiple of a sum of whole numbers with no common factor?

Zielflug [23.3K]

Use the distributive property to express the sum of the 2 whole numbers 15 and 30 with common factors as a multiple of two whole numbers with a sum of no common factor the solution would be (15 plus 30) = 15(1+2)

4 0

3 years ago

Read 2 more answers

The difference of this equation.

yaroslaw [1]

Answer:

$\frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}$

Step-by-step explanation:

$\frac{3y - 1}{(y-8)(y+8)} -\frac{3}{y+8} = \frac{3y - 1}{(y-8)(y+8)} -\frac{3(y-8)}{(y-8)(y+8)} =\\\\=\frac{3y - 1-3y+24}{(y-8)(y+8)} = \frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}$

4 0

3 years ago

Find the general term of {a_n}

Assoli18 [71]

From the given recurrence, it follows that

$a_{n+1} = 2a_n + 1 \\\\ a_{n+1} = 2(2a_{n-1} + 1) = 2^2a_{n-1} + 1 + 2 \\\\ a_{n+1} = 2^2(2a_{n-2}+1) + 1 + 2 = 2^3a_{n-2} + 1 + 2 + 2^2 \\\\ a_{n+1} = 2^3(2a_{n-3} + 1) + 1 + 2 + 2^2 = 2^4a_{n-3} + 1 + 2 + 2^2 + 2^3$