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Xelga [282]
2 years ago
5

-2x+1=7 how do I do this?

Mathematics
2 answers:
Agata [3.3K]2 years ago
7 0

Answer:

-3

Step-by-step explanation:

Write the equation down, the first step is to minus the one from both sides of the equal sign(since it’s the opposite then adding) so you cancel out the 1 and do 7-1 your equation would look like this : -2x=6 the next step is to divide the -2 (it’s the opposite of multiplication) your answer would be x=-3

ivanzaharov [21]2 years ago
5 0

Answer: x=-3


Step-by-step explanation: -2x+1=7

-2x=7-1

-2x=6

-2x/-2=6/-2

X=-3


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Anuta_ua [19.1K]

Answer:

3^{75}

Step-by-step explanation:

We are asked to divide our given fraction: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(3*15)^{45}=3^{45}*15^{45}

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Substituting these values in our division problem we will get,

\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}

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Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{45}*15^{60-30}}{5^{30}}

\frac{3^{45}*15^{30}}{5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{3^{45}*(3*5)^{30}}{5^{30}}

\frac{3^{45}*3^{30}*5^{30}}{5^{30}}

Upon canceling out 5^{30} we will get,

3^{45}*3^{30}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

3^{45+30}

3^{75}

Therefore, our resulting quotient will be 3^{75}.

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The first one is B
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