X = [ (i sqrt46) / (2) ] ; - [ (i sqrt46) / (2) ]
A) x = 8
B) a = 80
C) y = 7
D) c = 12
Hope this helped! :)
Answer:
B) 2\ sq.rt{3}units
Step-by-step explanation:
using Pythagoras theorem
a^2+ b^2=c^2
a^2+ 3^2=(√21)^2
a^2+9= 21
a^2=21-9
a^2=12
a=√12
a=2√3
Answer:
C
Step-by-step explanation:
Based on the other answers. C is the odd one out.
For an arithmetic sequence, the nth term is the first term plus (n-1)×the differece
the first term is 28, the difference between each adjacent number is 8
so -36=(28)+8(n-1)
8(n-1)=64
n-1=8
n=9
the 9th term is -36
