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4 years ago

IF YOU CAN HELP! That would be great!

Mathematics

2 answers:

iVinArrow [24]4 years ago

7 0

5x^2 - 6x^2 = - x^2 so its either c or d.

and + 9x - )-3x) = 9x + 3x = + 12x

so the answer s C.

UNO [17]4 years ago

5 0

5x2+9x+3
-6x2+3x
The answer is that you just solve it like this ==>-x2+12x+3
Finished!!
C is the answer!! ;)

You might be interested in

Find the are of the parallelogram 3 ft 7 ft

UkoKoshka [18]

Answer:

If you mean the area then 21ft

Step-by-step explanation:

3ft times 7ft= 21ft

Formula for area of parallelogram

A=BH

A=B times H

B is base and H is height

Hopefully that helps:)

4 0

4 years ago

Please help me! <br> please answer all questions

erastovalidia [21]

1) Distance = speed x time
time = distance/speed

time = 8054/715 = 11.26 hours or 11 h and 15 minutes (0.26 x 60 = 15.6)

2) The mode in a statistical series is the number that is repeated most or in short the highest frequency. In you example we notice that 12 is repeated twice, whereas the others are not repeated. Then the mode is 12.

3) The cost of each game = $17.99, so with his $65 he can buy:
65/17.99 = 3.61 . Obviously he can't buy 0.61 game, then he can buy
only 3 games (3 x 17.99 = $53.97) and keep in his pocket :
65 - 53.97 = $11.03

3 0

3 years ago

I need help with pre calculus.

otez555 [7]

Question 1

<h3>Answer: Choice A) -7</h3>

-----------------

Explanation:

To compute f(g(2)), we'll first need to find g(2).

Locate 2 in the x row. Then read straight down until you get to the g(x) row. You should find that g(2) = 4

This means f(g(2)) becomes f(4). We then repeat the same process as before. Locate 4 in the x row, read straight down til you get to the f(x) row to find that f(4) = -9

Overall, we can say f(g(2)) = -9

We do the same set of steps to compute g(f(-1)). You should find that f(-1) = -1 and g(f(-1)) = g(-1) = -2

Lastly, we subtract the results we got:

f(g(2)) - g(f(-1)) = -9 - (-2) = -9+2 = -7

==============================================

Question 2

<h3>Answer: Choice B) 0</h3>

-----------------

Explanation:

If you were to graph each equation, you should get what you see below.

The red and blue curves do not intersect in any way. We need an intersection point to have a solution. Because there are no intersections, we don't have any solutions. The system is considered inconsistent.

==============================================

Question 3

<h3>Answer: Choice B</h3><h3> $-2x^2+250x-2000$ </h3>

-----------------

Explanation:

x = number of scooters made and sold

Each scooter costs $150 to make. If you made x of them, then it costs 150x dollars. Then tack on the fixed cost of $2000 to get the expression $150x+2000$

The cost function is $C(x) = 150x+2000$ . We'll subtract this from the revenue function R(x) to get the profit P(x)

$\text{Profit} = \text{Revenue} - \text{Cost}\\\\P(x) = R(x) - C(x)\\\\P(x) = (400x-2x^2) - (150x+2000)\\\\P(x) = 400x-2x^2-150x-2000\\\\P(x) = -2x^2+250x-2000\\\\$

==============================================

Question 4

<h3>Answer: Choice B</h3>

$\left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}$

-----------------

Explanation:

$g(x) = \frac{1}{x+1}\\\\g(f(x)) = \frac{1}{f(x)+1}\\\\g(f(x)) = \frac{1}{x^2+x-3+1}\\\\g(f(x)) = \frac{1}{x^2+x-2}\\\\g(f(x)) = \frac{1}{(x+2)(x-1)}\\\\(g\circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\$

I started with the outer function g(x) and replaced each x with f(x) in the second step. Then I plugged in f(x) = x^2+x-3 and simplified. Factoring the denominator is helpful to determine where the denominator becomes zero. Specifically, it happens when x = -2 and x = 1. These x values must be kicked out of the domain to avoid a division by zero error.

So we start off with the real number line, and poke holes at x = -2 and x = 1.

The notation $x \in \mathbb{R}$ means x is a real number. Then we tack on $x \ne -2, x \ne 1$

Overall, the domain is $\left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}$

Let's see what happens if we tried plugging x = -1 into this composite function:

$(g \circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\(g \circ f)(-1) = \frac{1}{(-1+2)(-1-1)}\\\\(g \circ f)(-1) = \frac{1}{(1)(-2)}\\\\(g \circ f)(-1) = \frac{1}{-2}\\\\(g \circ f)(-1) = -0.5\\\\$