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BARSIC [14]
4 years ago
6

18 ft equals how many yd?

Mathematics
2 answers:
Licemer1 [7]4 years ago
8 0
6 because a yard is 3 feet
ololo11 [35]4 years ago
3 0

Answer:

6 Yards

Step-by-step explanation:


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The scale model of a rectangular garden is 1.5 ft by 4 ft. The scale model is enlarged by a scale factor of 7 to create the actu
LenaWriter [7]

It is given that the scale model of a rectangular garden is 1.5 ft by 4 ft. The scale model is enlarged by a scale factor of 7 to create the actual garden.

Therefore, we can see clearly that the width of the scale model is 1.5 feet. Hence, the width of the actual garden which has been enlarged by a scale factor of 7 will be 7 times the width of the scale model.

Thus the width of the actual garden will be: 1.5\times 7=10.5 feet

In a similar fashion the length of the actual garden will be 4\times 7=28 feet

Thus, the area of the actual garden will be:

Area=Length\times width=10.5\times 28=294 ft^2

As we can see, out of the given options, the last option is the correct one.

6 0
3 years ago
Read 2 more answers
Solve | x | < 10
Neko [114]

Answer:

Right answer is B) x>-10 and x<10

8 0
4 years ago
12+3x-x-12= equals in combine like terms
Katen [24]
The an answer is 2x


explanation :


12+3x-x-12

= 3x-x

= 2x
7 0
4 years ago
Pre college need help number 3
lubasha [3.4K]

Answer:

B) No solution

Step-by-step explanation:

Adding two numbers together for a signle result cannot result in two different numbers. Example.

-2 + 3 = 1

-2 + 3 ≠ 4

You can also use math. Using substitution will result in simplyfying -y and y, creating 0 with no variable to solve for.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

7 0
3 years ago
an airplane travels 5424 km against the wind in 8 hours and 6624 km with the wind in the same amount of time. what is the rate o
liq [111]

Answer:

The rate of the plane is 753 km/h while the rate of the wind is 75km/h

Step-by-step explanation:

Here in this question, we are interested in calculating the rate of the plane in still air and the rate of the wind.

Since we do not know these rates, we shall be representing both using variables.

Let’s represent the rate of the plane in still air by x kmph while the rate of the wind be represented by y kmph

Now, for us to calculate the speed of the plane while it travels against the wind, that would be the speed of the plane in still air minus the speed of the wind.

Mathematically, that would be (x-y) kmph

Now the speed of the plane while it travels with the wind would be its speed in still air plus the speed of the wind.

Mathematically, that would be;

(x + y) kmph

From the question;

The plane journeyed 5424 km against the speed in 8 hours, this means that its speed will be 5424/8 = 678 kmph

Thus, that means;

x -y = 678 •••••••(i)

Now, traveling with the wind , its speed will be ;

6624/8 = 828 kmph

Thus;

x + y = 828 kmph •••••••(ii)

So we have two equations to solve simultaneously;

Let’s add both together;

x -y + x + y = 828+ 678

2x = 1,506

x = 1506/2

x = 753 kmph

From ii

x + y = 828

y = 828 - x

y = 828 - 753

y = 75 kmph

5 0
3 years ago
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