2. Make a conjecture:<br> What do you think is the measure of the<br> angle of rotation?

Question Which of the following will justify that EFGH is a parallelogram?

Ber [7]

Answer:

D

Step-by-step explanation:

3 0

2 years ago

A pyramid has a base 16 inches x 16 inches and a slant height of 10 inches. what is the volume in cubic inches

gizmo_the_mogwai [7]

Answer:

512 in³

Step-by-step explanation:

The height perpendicular to the base is the leg of a right triangle with hypotenuse 10 in and other leg 8 in. Using the Pythagorean theorem, we can find it as ...

h² +8² = 10²

h² = 100 -64 . . . . . subtract 8²

h = 6 . . . . . . . . . . . . take the square root of 36

Then the volume is found using ...

V = (1/3)Bh = (1/3)(16 in)²(6 in) = 512 in³

The volume is 512 cubic inches.

_____

The 8-inch dimension used above comes from half the distance between the center of one side of the base to the center of the opposite side. (16 in)/2 = 8 in.

4 0

3 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

$(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0$

Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

8 0

3 years ago

Thirty-two cyclists make a seven-day trip. Each cyclist requires 8.33 kilograms of food for the entire trip. If each cyclist wan

kvasek [131]

Answer:

76.16 kilograms of food

Step-by-step explanation:

Number of cyclist = 32

Food per cyclist = 8.33 kilograms

Days of the trip = 7 days

Food per cyclist per day = 8.33 kg / 7

= 1.19kg food per day for each cyclist

how many kilograms of food will the group be carrying at the end of Day 5?

5 days out of 7 days = 2 days

Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days

= 2 × 1.19

= 2.38 kilograms of food for two days

32 cyclist for 2 days = 32 × 2.38 kg of food

= 76.16 kilograms of food

The group will be carrying 76.16 kilograms of food at the end of Day 5

3 0

2 years ago

Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(

Temka [501]

The particular quadratic solution to the ODE is found as follows:

$x=at^2+bt+c$
$x'=2at+b$

$(2at+b)+2(at^2+bt+c)=t^2+4t+7$
$2at^2+(2a+2b)t+(b+2c)=t^2+4t+7$

$\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4$

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

$x'+2x=0\implies r+2=0\implies r=-2$

so that $x_c=Ce^{-2t}$ is a characteristic solution to the ODE, and the general solution would be

$x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4$

4 0

3 years ago

2. Make a conjecture: What do you think is the measure of the angle of rotation?