Graphing trigometric functions
1 answer:
Answer:
Period of the function is 4π
Step-by-step explanation:
Given is a graph:
It oscillates between -1 and +1
The graph shows angles on x axis and trig values on y axis.
The graph has value +1 when x=0 and reaches minimum -1 when x =2pi and again reaches y=1 when x =4 π
Thus we find that this is a periodic function with amplitude 1 and phase shift 0 and period 4π
So we get the period of the trignometric funciton is 4π
So option 1 is right
Verify:
Given function is y = cos
Since parent function y =cosx has a period of 2pi, we have
here period = 2pi/coefficient of x in cos
=2pi/(1/2)
=4pi
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Answer:
2x -y ≥ 4
Step-by-step explanation:
The intercepts of the boundary line are given, so it is convenient to start with the equation of that line in intercept form:
... x/(x-intercept) + y/(y-intercept) = 1
... x/2 + y/(-4) = 1
Multiplying by 4 gives the equation of the line.
... 2x -y = 4
This line divides the plane into two half-planes. The half-plane that is shaded is the one for larger values of x and/or smaller values of y than the ones on the line. So, for some given y, if we increase x we will get a number from our equation above that is greater than 4. Hence, the inequality we want is ...
... 2x -y ≥ 4
We use the ≥ symbol because the line is solid, so part of the solution space.
