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3 years ago

Select the more electronegative element in each pair. O F O Br O s O o O N O P O K O Ca

Chemistry

2 answers:

Katyanochek1 [597]3 years ago

6 0

Answer:

More electronegative element in each pair

O & F ⇒ Fluorine is more electronegative.

O & Br ⇒ Oxygen is more electronegative.

O & S ⇒ Oxygen is more electronegative

O & N ⇒ Oxygen is more electronegative

O & P ⇒ Oxygen is more electronegative

O & K ⇒ Oxygen is more electronegative

O & Ca ⇒ Oxygen is more electronegative

Explanation:

Electronegativity is the measure pf tendency to attract bond pair electrons towards itself in a covalent bond.

More electronegative element attract bond pair electron from less electronegative element.

Electronegativity increases along the peroid when we move from left to right in perodic table and decreses down the group or top to bottom in periodic table.

So Oxygen, Fluorine, Chlorine and Nitrogen are the most electronegative among the all elements in periodic table.

andreyandreev [35.5K]3 years ago

5 0

Answer:

What im confused?

Explanation:

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3 years ago

What is the percent by mass of water in MgSO4 • 7H2O? A. 51.1% B. 195% C. 56.0% D. 21.0%

lbvjy [14]

Answer : The correct option is, (A) 51.1%

Explanation :

Mass percent : It is defined as the mass of the given component present in the total mass of the compound.

Formula used :

$\text{Mass} \%H_2O=\frac{\text{Mass of }H_2O}{\text{Mass of }MgSO_4.7H_2O}\times 100$

First we have to calculate the mass of $H_2O$ and $MgSO_4.7H_2O$ .

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Now put all the given values in the above formula, we get the mass percent of $H_2O$ in $MgSO_4.7H_2O$ .

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3 years ago

For which δg°rxn = –30.5 kj/mol at 37.0 °c and ph 7.0. calculate the value of δgrxn in a biological cell in which [atp] = 5.0 mm

mario62 [17]

We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:

ATP + H₂O → ADP + HPO₄²⁻

We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:

ΔGrxn = ΔG°rxn + RTlnQ

We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:

Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001

Now we can use the above formula to solve for ΔGrxn.

ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol

The value of ΔGrxn = -54.3 kJ/mol.

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