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kodGreya [7K]
3 years ago
9

What is required to cause acceleration or cause an object to move

Chemistry
2 answers:
OverLord2011 [107]3 years ago
7 0
A "FORCE" is required to cause acceleration or cause an object to move.
sleet_krkn [62]3 years ago
7 0
A force is required to cause acceleration or cause an object to move.
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Plz help me i swear will mark you brainiest :(
vladimir1956 [14]

Answer:

C. the relative molecular mass of the compound

Explanation:

Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.

7 0
3 years ago
Galvanized nails are iron nails that have been plated with zinc to prevent rusting. The relevant reaction is
fomenos

Answer:

1.18 × 10⁷ c

Iron is the anode and zinc is the cathode.

Explanation:

Let's consider the reduction of Zn²⁺.

Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)

<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>

<em />

We can establish the following relations:

  • When 2 moles of electrons circulate, 1 mol of Zn is produced.
  • 1 mole of electrons have a charge of 96468 c (Faraday's constant).

Then, for 61.2 mol of Zn:

61.2molZn.\frac{2mole^{-} }{1molZn} .\frac{96468c}{1mole^{-}} =1.18 \times 10^{7} c

<em>Identify the anode and cathode when plating an iron nail with zinc.</em>

The anode is where the oxidation takes place and the cathode is where the reduction takes place.

Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)

3 0
3 years ago
A copper wire is left outside on the ground for several weeks. Which
LiRa [457]

Answer:

c

Explanation:

the oxygen in the air and water from the rain caused oxidation causing the copper wire to become tarnished.

5 0
3 years ago
Read 2 more answers
What can be represented on paper or computer by using the Lewis Dot structure?
Genrish500 [490]

Answer:

option C is correct

Explanation:

4 0
4 years ago
At a particular temperature, K = 1.00×102 for the reaction: H2(g) + F2(g)= 2HF(g) In an experiment, at this temperature, 1.40 mo
horsena [70]

Answer:

0.20175 mol/L

Explanation:

The given equilibrium reaction and the equilibrium concentrations are shown below as:-

\begin{matrix}&H_2&+&F_2&\rightleftharpoons &2HF\\ At\ time, t = 0 &1.40&&1.40&&0\\At\ time, t=t_{eq}&-x&&-x&&+2x\\ ----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:-&1.40-x&&1.40-x&&2x\end{matrix}

The Kc of an equilibrium reaction measures relative amounts of the products and the reactants present during the equilibrium.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

The expression for the Kc is:-

K_c=\frac{[HF]^2}{[H_2][F_2]}

Given that:- Kc = 1.00\times 10^2

Thus, applying the values as:-

1.00\times 10^2=\frac{(2x)^2}{(1.40-x)(1.40-x)}

10^2=\frac{4x^2}{\left(1.4-x\right)^2}

100\left(1.4-x\right)^2=4x^2

Solving, we get that:-

x=1.17

Thus,  

[H_2]_{eq}=1.40-x=1.40-1.17=0.23\ moles

Given that:- Volume = 1.14 L

So, Molarity=\frac{0.23}{1.14}\ mol/L=0.20175\ mol/L

6 0
3 years ago
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