Answer:
C. the relative molecular mass of the compound
Explanation:
Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.
Answer:
1.18 × 10⁷ c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²⁺.
Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>
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We can establish the following relations:
- When 2 moles of electrons circulate, 1 mol of Zn is produced.
- 1 mole of electrons have a charge of 96468 c (Faraday's constant).
Then, for 61.2 mol of Zn:

<em>Identify the anode and cathode when plating an iron nail with zinc.</em>
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
Answer:
c
Explanation:
the oxygen in the air and water from the rain caused oxidation causing the copper wire to become tarnished.
Answer:
0.20175 mol/L
Explanation:
The given equilibrium reaction and the equilibrium concentrations are shown below as:-

The Kc of an equilibrium reaction measures relative amounts of the products and the reactants present during the equilibrium.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
The expression for the Kc is:-
Given that:- Kc =
Thus, applying the values as:-
Solving, we get that:-
Thus,
![[H_2]_{eq}=1.40-x=1.40-1.17=0.23\ moles](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D1.40-x%3D1.40-1.17%3D0.23%5C%20moles)
Given that:- Volume = 1.14 L
So, 