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prohojiy [21]
3 years ago
6

Erik correctly rounds three numbers. One and StartFraction 7 over 29 EndFraction rounds to 1 One and five-sixths rounds to 2 0.1

6 rounds to 0 Which shows the numbers One and StartFraction 7 over 29 EndFraction, One and five-sixths, and 0.16 in order from greatest to least?30pts
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

Step-by-step explanation:

1+7/29=29+7/29

=36/29

=1.24

Approximately

=1

1+5/6=6+5/6

=11/6

=1.83

Approximately

=2

0.16

Approximately =0

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

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Jessie estimated the weight of his cat to be 12 pounds. The actual weight of the cat is 15 pounds.
Juliette [100K]

Answer:

The correct answer is 20%

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5 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Evaluate 1/4 c + 3d when c = 6 and d = 7
Naddika [18.5K]

           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em>         </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

       Replace c with 6, and d with 7:-

     \Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}

\bigstar On simplification,

   \Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}

\bigstar On further simplification,

    \Large\text{$\displaystyle\frac{6}{4} +21$}

\bigstar On further simplification,

     \Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}

\bigstar Adding the numerators,

\Large\text{$\displaystyle\frac{90}{4}$}

\bigstar Finally, Reducing the fraction:-

\Large\text{$\displaystyle\frac{45}{2}$}

\Uparrow \mathbb{OUR\:SIMPLIFIED\:EXPRESSION}

<h3>Good luck with your studies.</h3>

         \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

8 0
2 years ago
Read 2 more answers
An icecream shop charges $3.39 for a dish of ice cream. A costomer can also order toppings for $0.59 each. If x represents the n
Leya [2.2K]

Answer:

3.39 + 0.59x

Step-by-step explanation:

Cost of a dish of ice cream = $3.39

Cost of toppings = $0.59 each

x = number of toppings

which expression can be used to determine the total charge in dollars, for a dish of ice cream with x toppings

Total charge for a dish of ice cream with x toppings = 3.39 + 0.59x

The expression is 3.39 + 0.59x

5 0
3 years ago
A ball is tossed up in the air at an initial rate of 50 ft/sec from 5 ft off the ground.
Fofino [41]

Answer with Step-by-step explanation:

Since we have given that

Initial velocity = 50 ft/sec = v_0

Initial height of ball = 5 feet = h_0

a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?

As we know the function for height h with respect to time 't'.

h(t)=-16t^2+v_0t+h_0\\\\h(t)=-16t^2+50t+5

b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).

What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?

if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time

Our function becomes,

h(t)=\int\limits^t_0 {-16t^2+50t+5} \, dt

3 0
3 years ago
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