For discontinuity of the function:
x² - 7 x - 8 ≠ 0
x² - 8 x + x - 8 = 0
x ( x - 8 ) + ( x - 8 ) ≠ 0
( x - 8 ) ( x + 1 ) ≠ 0
The points of discontinuity are: x = - 1 and x = 8.
As for the Domain of the function:
x ∈ ( - ∞, - 1 ) ∪ ( - 1 , 8 ) ∪ ( 8, +∞ ).
Answer:
yes
Step-by-step explanation:
As an example
(x₁, y₁ ) = (1,2) and (x₂, y₂ ) = (5,3), then
d =
=
=
= 
Now let (x₁, y₁ ) = (5,3) and (x₂, y₂ ) = (1,2), then
d =
=
=
= 
Answer:
Step-by-step explanation:
Formula
A = L * W
Givens
W = W
L = W + 2
Solution
Area = L*W
Area = (W+2)*W = 80 Remove the brackets.
Area = W^2 + 2W = 80 Subtract 80 from both sides.
Area = w^2+2W-80=80-80 Combine
Area = w^2 +2W-80 = 0 Factor.
Area = (w+10)(w - 8) = 0
W + 10 = 0 won't work
W = - 10 which isn't possible
W- 8 = 0
W = 8
L = 8 + 2 = 10
The answer looks like A
Answer:
y = -3 m = -1 b = 3
Step-by-step explanation:
-3y=3x-9
To isolate the y variable, divide both sides by -3.
y = -1x + 3
y = -3
m = -1
b = 3