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Vesnalui [34]
3 years ago
11

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. A rectangle is shown wi

th length x plus 10 and width 2 x plus 5. The inside of the rectangle is shaded other than an unshaded square with length x plus 1 and width x plus 1. Write an expression for the area of the shaded region in its simplest form. Show all of your steps.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

x² + 23x + 49

Step-by-step explanation:

Since the area of a rectangle is: A = l x w, where l = length and w = width, we can find the overall area of the shaded region by multiplying the entire area and subtracting the smaller area of the unshaded square:

(2x + 5)(x + 10) - (x + 1)² or (2x + 5)(x + 10) - (x² + 2x + 1)

Distribute/FOIL:  

2x² + 20x + 5x + 50 - x² - 2x -1

Combine like terms:

x² + 23x + 49

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Qu. In a triangle ABC, side AB has length 10cm, side AC has length 5cm, and angle BAC = θ
Vinil7 [7]

Answer:

To find cosθ, use the formula for the area of a triangle i.e. AREA=1/2 x a x b x sinC.=> For this case: 15= 1/2 x 10 x 5 x sinC to find sinC.=> SinC = 3/5 thus, Arcsin(3/5)=+- 4/5 or +-0.8

To find the exact length of BC, use the cosine rule.=> c(sq)=a(sq)+b(sq)-2abCosC=> c(sq)=10(sq)+5(sq)-2(10)(5)(+-4/5)=> c(sq)= Square root of 205

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3 years ago
Help with this question?? :c
mojhsa [17]
The answer is 1.52 to your question.
5 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
4 years ago
Given F(x) = V(3x – 12) + 2, what is the range in set notation?
iogann1982 [59]

Answer:

(-∞,∞)

Step-by-step explanation:

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3 years ago
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