How to work double reflections over parallel lines
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Hey there! :D
We will use the properties of similar triangles to figure this out.
We will use two triangles inside the kite, with sides with the value of "x".
Smaller triangle:
Smaller side= 11
Bottom side= x
Bigger triangle:
Smaller side= x
Bottom side= 25
Cross multiply.
25*11= 275
x*x=
Find the square root.
√275= 16.583....
Or 5√11.
I hope this helps!
~kaikers
We will use the properties of similar triangles to figure this out.
We will use two triangles inside the kite, with sides with the value of "x".
Smaller triangle:
Smaller side= 11
Bottom side= x
Bigger triangle:
Smaller side= x
Bottom side= 25
Cross multiply.
25*11= 275
x*x=
Find the square root.
√275= 16.583....
Or 5√11.
I hope this helps!
~kaikers
