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lesya692 [45]
4 years ago
5

a recipe uses 1 /1/4 cups of milk to make 10 servings if the same amount of milk is used for each serving how many servings can

be made using 1 gallon of mlik

Mathematics
1 answer:
Alona [7]4 years ago
5 0
Can you please help me

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natka813 [3]
5) all you have to do is calculate which would be 2.9166...
6) 65.898
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Business math question(can't figure out how to solve this one):
olga nikolaevna [1]

85i think the answer would be

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Patrick makes about 74% of his free throws when playing basketball. He shoots 40 free throws at practice. About how many free th
crimeas [40]

Answer:

about 30

Step-by-step explanation:

Convert 74% to  a decimal by dividing by 100 or by moving the decimal two places left.

74.% = 0.74

Multiply

0.74 x 40 = 29.6

Round to the nearest whole number

29.6 = 30

4 0
3 years ago
The graph of the equation y = 4x + 2 passes through the point (1, y).
EastWind [94]

Answer:

Graph.

y=4x+2(1,y)642X−6−4−2IN^46−2−4−6y−value(1,y)Y

Step-by-step explanation:

8 0
3 years ago
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According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a
Likurg_2 [28]

Answer:

1) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

X = 157 represent the women who worked at home who were college graduates

n = 480 the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

\hat p=\frac{X}{n} = \frac{157}{480}= 0.327

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 80% confidence interval the value for the significance is\alpha=1-0.8=0.2 and \alpha/2=0.1, the critical value would be given by:

z_{\alpha/2}=0.539

And replacing we goot:

0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

6 0
3 years ago
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