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qwelly [4]
3 years ago
7

Considering current online newspaper editions and the characteristics of digital age media, how do you think newspaper design mi

ght change in the future?
A.

Print newspapers will remain the same.


B.

Newspapers will be only available in an interactive online edition in industrialized nations.


C.

Newspapers, including online editions, will be completely eliminated.


D.

Newspapers will remove photos, graphics, and advertisements from their pages.
Computers and Technology
1 answer:
NeX [460]3 years ago
6 0
One way that a newspaper design may change in the future is that they will only be available in an interactive online edition. The correct answer is B. <span />
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The DNS server at your headquarters holds a standard primary zone for the abc domain. A branch office connected by a slow WAN li
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In the SOA tab of the zone's Properties dialog box, increase the refresh interval.

Explanation:

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When you save something to the Desktop on a school computer, what drive letter will it save to
Natali [406]

When you save something to the Desktop on a school computer, the drive letter it will save to the C drive.

<h3>What is a C drive?</h3>

C drive is that part of the computer that contains the operating system and files of the system. The files on which we worked are saved on the C drive of the system.

This is a type of hard drive. The work we have done on the system is automatically saved on the drive. We can easily find the C drive on the computer's file explorer. It automatically saved the data, but you can save manually the data of the D drive.

Thus, the drive letter it will save to the C drive.

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2 years ago
A a a a I don't need help!?
Arlecino [84]

Answer:

ok

Explanation:

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3 years ago
What's a good drawing tablet?
DENIUS [597]

Answer:

Wacom Intuos S

Explanation:

If you're looking for a good tablet that isn't too expensive the Wacom Intuos S is a great starter, I personally use it and really enjoy it. It doesn't have a graphic screen. If you're looking for one with a graphic screen get the Wacom Cintiq 22, It's expensive but great quality. Most tablets with a graphic screen are this expensive though. But if you REALLY want one with a graphic screen that isn't TOO expensive I recommend the HUION Kamvas pro 12.

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Read 2 more answers
It is a well-researched fact that men in a restroom generally prefer to maximizetheir distance from already occupied stalls, by
Artyom0805 [142]

Answer:

The code below addresses the problem statement with appropriate comments for explanation.

Explanation:

public class Stall

{

public static void main(String[] args)

{

boolean[] arr = new boolean[10];

while(hasFreeSpots(arr))   // as long as there is a free slot

{

arr[position(arr)] = true;  

// position(arr) gets the position of slot a person would most likely enter at(view problem statement)

// setting that position true(position occupied) by arr[position(arr)]

System.out.println(stallView(arr));   // printing current state of the stall using 'X' and '_'

}

}

/**

* Find the empty position that is in the middle of the sub-array of largest group of empty spots

* @param arr an array of boolean values

* @return returns an an integer value. Optimal position to be occupied.

*/

public static int position(boolean[] arr)

{

int first = 0;   // first stores the starting position of "longest sequence of unoccupied places"

int last = 0;   // last stores the ending position of "longest sequence of unoccupied places"

int temp1 = 0;   // temp1 stores the starting position of "current sequence of unoccupied places"

int temp2 = 0; // temp2 stores the ending position of "current sequence of unoccupied places"

 

for(int i = 0; i < arr.length; i++)   // for each slot in the Stall

{    

if(!arr[i]) // if slot i is not occupied

{    

temp1 = i;   // store starting position of "current sequence of unoccupied places" in temp1

while(i < arr.length && !arr[i] )   // if i is a valid index and as long as this slot is not occupied increment i

{

i++;

}

// we break out of the loop either if i is invalid index(reached end of the array)

// or if the slot is occupied by a person already

temp2 = i;   // store ending position of "current sequence of unoccupied places" in temp2

if(Math.abs(first - last) < Math.abs(temp1 - temp2))

  // if current sequence is longer than longest sequence, update it

{

first = temp1;

last = temp2;    

}

}

}

return (first + last) / 2;   // return middle index of first and last

}

/**

* Checks if there are empty spots in an array, basically checks if there is a false boolean value

* thats representing an empty spot in an array

* @param arr the input array, of boolean values

* @return returns a boolean value, true if there are false elements inside the array

*/

public static boolean hasFreeSpots(boolean[] arr)

{

boolean rtn = true;   // initializing rtn to 'true'

for(int i = 0; i < arr.length; i++)   // for every slot in the Stall

{

if(!arr[i]){rtn = false;}   // sets rtn to false if a free spot found

}

return !rtn;   // returns true if a free spot found and returns false if no free spot found

}

/**

* X for true, _ for false. Representing occupied(X) and free stalls(_)

* @param arr a boolean array

* @return returns a string representation if the input

*/

public static String stallView(boolean[] arr)

{

String str = "";       // initializing str to be an empty String

for(int i = 0; i < arr.length; i++)   // for every slot in Stall

{

if(arr[i]){str += " X";}   // Add X to str if slot is occupied

else {str += " _";}           // prints _ to str if slot not occupied

}

return str;       // return str(pictorial representation of Stall with 'X', '_')

}

}

7 0
3 years ago
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