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lesantik [10]
3 years ago
14

The DNS server at your headquarters holds a standard primary zone for the abc domain. A branch office connected by a slow WAN li

nk holds a secondary zone for abc. Updates to the zone aren't frequent. How can you decrease the amount of WAN traffic caused by the secondary zone checking for zone updates?
Computers and Technology
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

In the SOA tab of the zone's Properties dialog box, increase the refresh interval.

Explanation:

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nikitadnepr [17]

Answer:

Check the explanation

Explanation:

<u>The Code</u>

#include <fstream>

#include <iostream>

#include <cmath>

#include <cstring>

#include <cstdlib>

#include <ctime>

using namespace std;

//Function Declarations

void fillArrayWithRandNos(int nos[],int size);

void displayArray(int nos[],int size);

double mean(int nos[],int size);

double variance(int nos[],int size);

double median(int nos[],int size);

int mode(int nos[],int size);

void histogram(int nos[],int size);

int main() {

  //Declaring variables

const int size=100;

srand(time(NULL));

 

// Creating array dynamically

int* nos = new int[size];

 

//Calling the functions

fillArrayWithRandNos(nos,size);

displayArray(nos,size);

cout<<"Mean :"<<mean(nos,size)<<endl;

cout<<"variance :"<<variance(nos,size)<<endl;

cout<<"Median :"<<median(nos,size)<<endl;

cout<<"Mode :"<<mode(nos,size)<<endl;

histogram(nos,size);

 

  return 0;

}

void fillArrayWithRandNos(int nos[],int size)

{

  for(int i=0;i<size;i++)

  {

      nos[i]=rand()%(45) + 55;

  }

}

void displayArray(int nos[],int size)

{

  cout<<"Displaying the array elements :"<<endl;

  for(int i=0;i<size;i++)

  {

      cout<<nos[i]<<" ";

      if((i+1)%10==0)

      cout<<endl;

  }

}

double mean(int nos[],int size)

{

  double sum=0;

  for(int i=0;i<size;i++)

  {

      sum+=nos[i];

  }

  return sum/size;

}

double variance(int nos[],int size)

{

  double avg=mean(nos,size);

 

double variance,sum=0;

for(int i=0;i<size;i++)

{

sum+=pow(nos[i]-avg,2);

}

//calculating the standard deviation of nos[] array

variance=(double)sum/(size);

return variance;

}

double median(int nos[],int size)

{

      //This Logic will Sort the Array of elements in Ascending order

  int temp;

  for (int i = 0; i < size; i++)

{

for (int j = i + 1; j < size; j++)

{

if (nos[i] > nos[j])

{

temp = nos[i];

nos[i] = nos[j];

nos[j] = temp;

}

}

}

 

int middle;

float med;

middle = (size / 2.0);

if (size % 2 == 0)

med = ((nos[middle - 1]) + (nos[middle])) / 2.0;

else

med = (nos[middle]);

return med;

}

int mode(int nos[],int size)

{

  int counter1 = 0, counter2, modevalue;

for (int i = 0; i < size; i++) {

counter2 = 0;

for (int j = i; j < size; j++) {

if (nos[i] == nos[j]) {

counter2++;

}

if (counter2 > counter1) {

counter1 = counter2;

modevalue = nos[i];

}

}

}

if (counter1 > 1)

return modevalue;

else

return 0;

}

void histogram(int nos[],int size)

{

  int hist[9]={0};

  for(int i=0;i<size;i++)

  {

      if(nos[i]>=55 && nos[i]<=59)

      {

      hist[0]++;

      }

      else if(nos[i]>=60 && nos[i]<=64)

      {

      hist[1]++;

      }

      else if(nos[i]>=65 && nos[i]<=69)

      {

      hist[2]++;

      }

      else if(nos[i]>=70 && nos[i]<=74)

      {

      hist[3]++;

      }

      else if(nos[i]>=75 && nos[i]<=79)

      {

      hist[4]++;

      }

      else if(nos[i]>=80 && nos[i]<=84)

      {

      hist[5]++;

      }

      else if(nos[i]>=85 && nos[i]<=89)

      {

      hist[6]++;

      }

      else if(nos[i]>=90 && nos[i]<=94)

      {

      hist[7]++;

      }

      else if(nos[i]>=95 && nos[i]<=99)

      {

      hist[8]++;

      }

  }

     

  cout<<"Displaying the count of numbers in each interval:"<<endl;

 

      int cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|"<<hist[cnt]<<endl;

 

      cnt++;

  }

 

  cout<<"Displaying the histogram :"<<endl;

  cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|";

  for(int j=0;j<hist[cnt];j++)

  {

      cout<<"*";

  }  

      cout<<endl;

      cnt++;

  }          

     

 

 

}

#########

___________________________

The output can be seen in the attached image below.

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3 years ago
Which role involves designing and creating advertisements for marketing purposes?
satela [25.4K]

advertising designers

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3 years ago
Peter is software designer working at a big software company. He just found out that he has been shifted to their downtown branc
sweet [91]

The managers at Peter’s company have an Autocratic environment.

<u>Explanation:</u>

The managers who are autocratic in nature make decisions on their own. They will never get insights of their employees and they will not take the inputs of them in taking any decisions. This type of management is suitable in an organisation where there is an urgent need to taking decisions to any matter.

Managers who are autocratic in nature will make decisions without consulting anyone's advice.  This type suits those organisations wherein there are very less number of employees. Here, the manager of Peter did not consulted peter in making decisions related to him, the environment is authoritarian or autocratic.  

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3 years ago
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