Answer:
i tihnk it would be just -3
Step-by-step explanation:
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
If your solvung for x the answer will be X= 6y
Answer:
(-2x - 1) • (x + 3)
Step-by-step explanation:
3.2 Factoring 2x2 + 7x + 3
The first term is, 2x2 its coefficient is 2 .
The middle term is, +7x its coefficient is 7 .
The last term, "the constant", is +3
Step-1 : Multiply the coefficient of the first term by the constant 2 • 3 = 6
Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 7 .
-6 + -1 = -7
-3 + -2 = -5
-2 + -3 = -5
-1 + -6 = -7
1 + 6 = 7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 6
2x2 + 1x + 6x + 3
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x+1)
Add up the last 2 terms, pulling out common factors :
3 • (2x+1)
Step-5 : Add up the four terms of step 4 :
(x+3) • (2x+1)
Which is the desired factorization
Answer: 8(3-2x)(x+5), -16x^2-56+120, x=-5, or x=3/2.
Step-by-step explanation:
First convert the multi fraction into multiplication: 8(3-2x)(x+5)
Then simplify: -16x^2-56+120
If you want, you can solve for x, which gets you x=-5, or x=3/2.
I hope this helps! :P
