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Alekssandra [29.7K]
2 years ago
15

What is the correct method for solving 20+4x=24

Mathematics
2 answers:
never [62]2 years ago
4 0
-20 both sides then u get 4x=4 ÷ by 4 u get 1
blsea [12.9K]2 years ago
3 0
Add 20 to 24 and divide everything by 4
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Write the equation of the line that is parallel to the line and through the given point y=-2x+1 point (0,5)
marysya [2.9K]

Answer:

y = -2x+5

Step-by-step explanation:

y = -2x+1 is in the form y= mx+b where m is the slope and b is the y intercept

-2 is the slope

Parallel lines have the same slope so our new line will have the same slope

y = -2x+b

The point given is the y intercept (value when x is zero)

b = 5

y = -2x+5

5 0
2 years ago
What is the answer of -3 2/3 + 1.1 as a fraction?
pickupchik [31]
- 3 \frac{2}{3} + 1.1 = - \frac{11}{3} + \frac{11}{10} = - \frac{110}{30} + \frac{33}{30} \\ = -\frac{77}{30} = -2 \frac{17}{30}
7 0
3 years ago
A team spent 20 mins on passing drills and 40 minuets ona shooting drill, what is the ratio of time spent on shooting drills to
aliya0001 [1]
20 minutes on passing .....40 minutes on shooting

ratio of time spent on shooting to passing....
these are not hard, u just have to pay attention to the wording...

the ratio of shooting to passing is 40/20 which reduces to 2/1 or 2:1 or
2 to 1 <===

but if it would have asked for passing to shooting, it would have been :
20/40 which reduces to 1/2 or 1:2 or 1 to 2

so ur answer is 2/1 or 2:1 or 2 to 1
6 0
3 years ago
Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
Helpp worth 20 points!!<br>write the equation of the line below<br><br>​
Anit [1.1K]

Answer:

y = -x -2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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