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eduard
3 years ago
13

Please solve this :)

Mathematics
1 answer:
scoray [572]3 years ago
5 0

Answer:

Step-by-step explanation:

hello :

cos66° = x/14

x= 14× cos66°

x= 14× 0.41

x=5.74

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QUESTION 16<br> What is the absolute value of -72?
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The absolute value of -72 is 72.

Absolute value is essentially just making the number given positive.

If the given number is already positive then the absolute value is the same as the original number

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1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.
iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is 53.13\°

Part 2) The surface area of the pyramid is 288\ cm^{2}

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

sin(x)=\frac{16}{20}

x=arcsin(\frac{16}{20})=53.13\°

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}(b)(h)]

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

h=b/2 -------> by an 45° angle

so

b=2h

sin(45\°)=\frac{h}{6\sqrt{2}}

h=6\sqrt{2}(sin(45\°))=6\ cm

Find the value of b

b=2(6)=12\ cm

Find the surface area

SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}

3 0
3 years ago
Can someone find r please
katrin2010 [14]

Answer:

r = 3 \times \sqrt{2}

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

c = \sqrt{72}

c = \sqrt{36 \times 2}

c = \sqrt{36} \times \sqrt{2}

c = 6 \times \sqrt{2}

c is the diameter.

r is the radius, so it is half of the diameter.

c = d

r = d/2

r = \dfrac{d}{2} = 3 \times \sqrt{2}

8 0
3 years ago
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