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eduard
3 years ago
13

Please solve this :)

Mathematics
1 answer:
scoray [572]3 years ago
5 0

Answer:

Step-by-step explanation:

hello :

cos66° = x/14

x= 14× cos66°

x= 14× 0.41

x=5.74

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Write an inequality for the situaions below and solve:
musickatia [10]

Answer

Find out the how many boxes of paper can the forklift move at one time .

To proof

Let us assume that the number of boxes be x.

As given

A forklift can carry up to 2500 pounds.

You want to move boxes of paper which each weigh 140 pounds.

The paper boxes are supported on one pallet which weighs 50 pounds.

Than the equation is become in the form

140x +50  ≥ 2500

140x ≥ 2500 - 50

140x ≥ 2450

x \geq \frac{2450}{140}

x ≥ 17.5

Therefore the 18 boxes of paper can the forklift move at one time .

Hence proved

5 0
3 years ago
A phone company surveys a sample of current customers to determine if they use their phones most often to text or use the Intern
Gre4nikov [31]

Answer: payment B: 23 customers

plan B text: 13 customers

fraction form: 13/23

Step-by-step explanation:

7 0
3 years ago
"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"
erastovalidia [21]

Answer:

The exam can be answered with exactly 8 answers correct in 6435 ways.

Step-by-step explanation:

The order is not important.

For example, answering correctly the questions 1,2,3,4,5,6,7,8 is the same outcome as answering 2,1,3,4,5,6,7,8. So we use the combinations formula to solve this problem.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

Combinations of 8 questions from a set of 15. So

C_{15,8} = \frac{15!}{8!(15-8)!} = 6435

The exam can be answered with exactly 8 answers correct in 6435 ways.

5 0
3 years ago
Iodine-125 has a half-life of about 60 days.
Murljashka [212]

62.5 mg sample will remain after 240 days

Step-by-step explanation:

Given

Half-life = T =  60 days

The formula for calculating the quantity after n half lives is given by:

N = N_0(\frac{1}{2})^n

Here

N is the final amount

N_0 is the initial amount

n is the number of half lives passed

The number of half lives are calculated by dividing the time for which the remaining quantity has to be found by half life

The quantity has to be calculated for 240 days so,

n = \frac{240}{60}\\n = 4

Given

N_0 = 1000\ mg

Putting the values in the formula

N = 1000 (\frac{1}{2})^4\\=1000 * \frac{1}{16}\\=\frac{1000}{16}\\=62.5\ mg

Hence,

62.5 mg sample will remain after 240 days

Keywords: Half-life, sample

Learn more about half-life at:

  • brainly.com/question/11286417
  • brainly.com/question/12973601

#LearnwithBrainly

3 0
3 years ago
Question 5
mezya [45]

Answer:

Value is 15 and measure is 151

3 0
3 years ago
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