Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
9/35
all the boxes in one row are 7 and the number of rows are 5 .. so 7x5=35 and the number of boxes shaded are 9
How to solve this: (in case you need it)
4n-18=52
4n-18+18=52+18
4n=70
4n/4=70/4
n=35/2
Answer: 2900185 Joules
Step-by-step explanation:
Force used to tow the car is 1600N
Angle(α)= 25
Displacement = 2km
Recall that 1km= 1000m
Therefore 2km= 2000m
Workdone= FdCos α
W= 1600 * 2000 * cos 25
W=2900184.919
W= 2900185 Nm(when approximated to the nearest integer)
Since 1J = 1Nm
Work done = 2900185 J
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