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3 years ago

15

Solve each system by substitution: {y = -x + 5, 2x + y = 11

1 answer:

lilavasa [31]3 years ago

5 0

I hope this picture helps. I'll elaborate if needed!

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The temperature is 50 degrees Fahrenheit. The temperature will decrease by 4 degrees F. each hour. Let h be the number of hours.

goblinko [34]

The correct answer choice is B

8 0

3 years ago

Read 2 more answers

The square of a positive number is 24 more than 5 times a number. What is the value of the number?

Mars2501 [29]

X² = 24+5y

y=5 and x=7

8 0

3 years ago

According to The Wedding Report, Inc., the mean cost for a wedding in the United States is $28732 (as of November 2008). Suppose

Stella [2.4K]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

$X = \text{cost of wedding}\sim \text{Normal}\ (\mu = 28732, \sigma= 1500)\\\\$

For point a:

$Probability\ = 0.00000359\\\\ \text{(Using Excel function:} =NORMDIST(22000,28732,1500,1)).$

For point b:

$Probability \ = 0.014678\\\\\text{(Using Excel function:} =1-NORMDIST(32000,28732,1500,1))\\\\$

For point c:

$Probability\ = 0.794614436 \\\\$

$\text{(Using Excel function:} \\=NORMDIST (30000,28732,1500,1)-NORMDIST(25000,28732,1500,1))\\\\$

For point d:

$Q_1 = 27720.26537 \\\\\text{(Using Excel function:} =NORMINV(0.25,28732,1500)) \\\\Q_3 = 29743.73463 \\\\\text{(Using Excel function:} =NORMINV(0.75,28732,1500)).$

For point e:

$IQR = Q_3 - Q_1 = 29743.73463 - 27720.26537 = 2023.469251.$

For point f:

$Top\ 10\% = 30654.32735 \\\\\text{(Using Excel function:} =NORMINV(0.9,28732,1500)).$

5 0

3 years ago

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

3 years ago

How to solve this substitution

Lena [83]

-5x+4y=11
substitute for x which is 5
(-5)(5)+4y=11

simplify :
4y-25=11

add 25 on both sides
4y-25=11
+25 +25
the 25 cancels out

so it would be 4y=36
and you divide both sides by 4

4/4 =36/4

which gives you (5,9)
x= 5 , y =9

6 0

3 years ago