Answer:
Step-by-step explanation:
Hi there! I'm glad I was able to help you solve this equation!
Let's start by simplifying both sides of the equation. It's easier to solve it this way!
Distribute:
Combine 'like' terms:
Next, you'll want to add 36 to both sides of the equation.
Finally, divide both sides by 
.
I hope this helped you! Leave a comment below if you have any further questions! :)
Answer:
2 gallons
since each pitcher holds 2 quarts of water and 4 quarts= 1 gallon, Desta poured 2 gallons of water into her cooler
Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
#SPJ1
Substitute y = 15x to the equation y = 25 + 12.5x:
15x = 25 + 12.5x <em>subtract 12.5x from both sides</em>
2.5x = 25 <em>divide both sides by 2.5</em>
x = 10
Substitute the value of x to the equation y = 15x:
y = (15)(10)
y = 150
<h3>
Answer: x = 10 and y = 150</h3>
